📘 Current Electricity – Circuits – 9 Most Important NEET Physics Problems With Detailed Step by Step Solutions

This section includes many important NEET Physics problems in Circuits topic of Current Electricity concepts that are considered to be very important from NEET exam point of view. Here the solutions for these problems are very detailed with explanation for each step. This section is very helpful for students to get very high scores in NEET.

NEET Physics Problems in Circuits topic in Current Electricity concepts And Their Solutions with Detailed Step by Step Explanation.

Ray Optics – Concave Mirror

Problem :1

If four resistances are connected as shown in the figure, the effective resistance between A and B is:

Options:
(1) 4 Ω (2) 8 Ω (3) 2.4 Ω (4) 2 Ω

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Step-by-step Solution:

Step 1: Identify the paths

We identify three paths starting from A but only two paths ending at B:

• Upper path: 4Ω
• Middle path: 6Ω and 1.6Ω
• Lower path: 4Ω

Step 2: Use Parallel formula to simplify the circuit

\( \frac{1}{R} = \frac{1}{R_{1}} + \frac{1}{R_{2}} \)

• 4Ω and 6Ω are in parallel: \( \frac{1}{R} = \frac{1}{4} + \frac{1}{6} \)
• R = \( \frac{6 \times 4}{10}\)
• R = 2.4Ω

Step 3: Use Series formula to further simplify

R = \( R_{1} + R_{2} \)

• 2.4Ω is in series with 1.6Ω
• \( \therefore R = 2.4 + 1.6 \)
• \( \Rightarrow R = 4Ω \)

Step 4: Finally apply the parallel resistors formula

• Two 4Ω resistors are in parallel
• \( \therefore \frac{1}{R} = \frac{1}{4} + \frac{1}{4} \)
• \( \Rightarrow R = \frac{4}{2}\)
• \( \Rightarrow R = 2 Ω \)

✅ Final Answer:

The effective resistance of the given circuit is :

2 Ω

(4) 2 Ω